1 g of magnesium is burnt with 0.56
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1.0g of magnesium is burnt with 0.56g O2(oxygen) in a closed vessel . Which reactant is left in excess and how much ? (At. wt. Mg = 24 ; O = 16)
Answered by admin @
The equation is as follows:
2Mg + O2 ------> 2MgO
(s) (g) (s)
Therefore 2 moles of Mg require 1 mole of O2 to produce 2 moles of MgO.
Calculate actual moles.
moles= mass/ molar mass
Mg= 1/24 = 0.041667
O2= 0.56/32 = 0.0175
MgO=
Mole ratio of Mg: O2 = 2:1
find mass of Mg that reacts:
that means 2 mole of Mg reacts with 1 moles of O2
If 1 = 2
Then 0.0175 = 0.0175 x 2
=0.035 moles of magnesium
mass of magnesium that reacts:
mass= moles x molar mass
= 24 x 0.035
0.84 g
That means that of the 1 gram of magnesium that reacts only 0.84 grams is used
Therefore magnesium is in excess and by 0.16
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